• 做CTF crypto时遇到了棋盘密码，写了个脚本
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    polybius = [[0,0,0,0,0,0],
                [0,'A','B','C','D','E'],
                [0,'F','G','H','I','K'],
                [0,'L','M','N','O','P'],
                [0,'Q','R','S','T','U'],
                [0,'V','W','X','Y','Z']]
                
    polybius2 = [[0,0,0,0,0,0],
                [0,'b','t','a','l','p'],
                [0,'d','h','o','z','k'],
                [0,'q','f','v','s','n'],
                [0,'g','i','c','u','x'],
                [0,'m','r','e','w','y']]
                
    def adfgx_to_num(my_str):
        my_str = my_str.upper()
        l_m = len(my_str)
        s_num = ""
        for i in range(l_m):
            t = my_str[i]
            if t == "A":
                s_num += "1"
            elif t == "D":
                s_num += "2"
            elif t == "F":
                s_num += "3"
            elif t == "G":
                s_num += "4"
            elif t == "X":
                s_num += "5"
            else:
                pass
        return s_num
        
    def decode_polybius1(c_str):
        s1 = ""
        l_c = len(c_str)
        for i in range(0,l_c,2):
            t = c_str[i:i+2]
            data = polybius[int(t[0])][int(t[1])]
            s1 += data
        print(s1)
        
    def decode_polybius2(c_str):
        c_str = adfgx_to_num(c_str)
        s1 = ""
        l_c = len(c_str)
        for i in range(0,l_c,2):
            t = c_str[i:i+2]
            data = polybius2[int(t[0])][int(t[1])]
            s1 += data
        print(s1)
        
    def main():
        c_str = "2315313134"
        decode_polybius1(c_str)
        c_str = "DDXFAGAGDF"
        decode_polybius2(c_str)
        print("如果语境不通，i 改为 j")
        
    if __name__ == "__main__":
        main()